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Resolving nodes of a plane curve

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Archived series ("Inactive feed" status)

When? This feed was archived on December 09, 2017 16:01 (6+ y ago). Last successful fetch was on October 29, 2017 08:04 (6+ y ago)

Why? Inactive feed status. Our servers were unable to retrieve a valid podcast feed for a sustained period.

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Manage episode 185577042 series 1521141
Content provided by Random Stuffs. All podcast content including episodes, graphics, and podcast descriptions are uploaded and provided directly by Random Stuffs or their podcast platform partner. If you believe someone is using your copyrighted work without your permission, you can follow the process outlined here https://player.fm/legal.
Let X be the Zero of f(z,w) and p a node. Then the quadratic terms of the Taylor series expansion of f at p factors into distinct linear factors which lift to f= gh. Around p, the zeroes of X looks like zeroes X_g union with X_h. Delete p from all three and glue them together. The result is a Riemann surface (if f is irreducible) since at least near p, X-p is a Riemann surface, being a nonsingular curve; X_g and X_h are Riemann surfaces by implicit function theorem (by changing coordinate we get g= x + .. so dg/dx(p) is not Zero and hence locally g looks like graph of a function of y) In case of projective plane curve cut out by irred f, the result is a compact Riemann surface.
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172 episodes

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Archived series ("Inactive feed" status)

When? This feed was archived on December 09, 2017 16:01 (6+ y ago). Last successful fetch was on October 29, 2017 08:04 (6+ y ago)

Why? Inactive feed status. Our servers were unable to retrieve a valid podcast feed for a sustained period.

What now? You might be able to find a more up-to-date version using the search function. This series will no longer be checked for updates. If you believe this to be in error, please check if the publisher's feed link below is valid and contact support to request the feed be restored or if you have any other concerns about this.

Manage episode 185577042 series 1521141
Content provided by Random Stuffs. All podcast content including episodes, graphics, and podcast descriptions are uploaded and provided directly by Random Stuffs or their podcast platform partner. If you believe someone is using your copyrighted work without your permission, you can follow the process outlined here https://player.fm/legal.
Let X be the Zero of f(z,w) and p a node. Then the quadratic terms of the Taylor series expansion of f at p factors into distinct linear factors which lift to f= gh. Around p, the zeroes of X looks like zeroes X_g union with X_h. Delete p from all three and glue them together. The result is a Riemann surface (if f is irreducible) since at least near p, X-p is a Riemann surface, being a nonsingular curve; X_g and X_h are Riemann surfaces by implicit function theorem (by changing coordinate we get g= x + .. so dg/dx(p) is not Zero and hence locally g looks like graph of a function of y) In case of projective plane curve cut out by irred f, the result is a compact Riemann surface.
  continue reading

172 episodes

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