Best fis podcasts we could find (Updated October 2017)
Related podcasts: Kory Comedy Featured FM Silverscreen Ski Slipgate9 Edict Edictzero Slater Zero Shows Series Drama Fun Media Movies Tv Film Audio Fiction  
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show episodes
 
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Edict Zero - FIS
Rare
 
Edict Zero - FIS is a science fiction audio drama series produced by Slipgate Nine Entertainment. It is a cross of futuristic sci-fi, law enforcement procedural, crime, suspense/mystery, and dark fantasy.
 
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F is for Film
Weekly
 
As informative as half- assery permits, our three heroes Beanie, Dre, and Trent delve into all things film and TV related.
 
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Edict Zero – FIS
Rare
 
Home of the Science Fiction Audio Drama series
 
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Who the F is Kory Slater?
Monthly+
 
Detailing the process of starting a comedy career in Los Angeles.
 
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C'Mon Son! The Podcast.
Weekly
 
C'Mon Son! The Podcast is hip-hop hall-of-fame inductee and Yo! MTV Raps legend Ed Lover's take on pop culture. Raw, rugged and unfiltered, this podcast gives listeners a break from "the expected," and will leave them wondering (while laughing hysterically), "what the f*** is wrong with Ed Lover?"
 
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HEAD TYROLIA (en) Bode Miller Special
 
HEAD TYROLIA Podcast Special – Bode Miller
 
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Elite Force Podcast
Monthly+
 
This Podcast Hosted By William" Walkie" Walker and Ashley Richardson as they brings you the News That is Going on in the World of Science Fiction. EFP is also Known for its Theme shows called EFP Presents. Past theme shows have covered Sci-Fis’ past and present in Tv,Movies,Video Games and Music. You Can Find The Elite Force Podcast at www.eliteforcepodcast.com
 
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M-F
Monthly+
 
M-F is a weekly daily podcast hosted by Sean and Amy. Link in bio.
 
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F's it all about ?
Rare
 
F's it all about ?What the F is it all about though? ...Conor & Dan take you through some of the common themes that millennials struggle to ascertain some meaning and satisfaction from in their everyday lives. Each episode is poised around one of these themes.
 
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CMD-F
Monthly
 
CMD-F is a podcast that aims to find and elevate stories that showcase exceptional people, places and things in Iowa City and beyond. Hosted by Alex Rose.
 
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What We Talkin Podcast & Convos With Drizz
 
Whats Going On People Listen Each Week As I Post Sit down Interviews With Artist And DJs In The Music Scene Of Manchester Plus Episodes Of The 'What We Talking' Podcast Talkin On Subjects About What The F*** Is Cracking Da2Day With Different Guests.DrizzCurrently On Legacy 90.1 Saturday From 6PM
 
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show series
 
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GameEnthus Podcast - video games and everything else
 
GameEnthus Podcast ep323: MetaRoidVania or VREnthus This week Frank(@PSVRFrank) from YouTube joins Tiny(@Tiny415), Mike(@AssaultSuit) and Aaron(@Ind1fference) talk about: PSVR, HTC Vive, Weeping Doll, The Rift Report, Taco Bell, Cookout, PS Move, CheapassGamer, Star Trek Discovery, 60 Minutes, Sin and Punishment, Rakuga Kids, Sonic, Boogie Man, ...…
 
The "Music Connection Magazine Podcast" hosts - Randy Thomas and Arnie Wohl are back at it again, as they are rejoined by Senior Editor of the Music Connection Magazine Mark Nardone, who recaps the viral effect of the Foo Fighters: Dave Grohl's Storytelling segment from episode one. Randy & Arnie are also joined in-studio by guest Eric Vasquez ...…
 
Seven new languages, including Rohingya, Tibetan and Telugu, will receive their own SBS language programs while others are being discontinued after a review of the services. The changes are aimed at reflecting the evolving needs of communities in Australia today. - Tħabbar it-tibdil fil-programmi fuq ir-Radju tal-SBS, li se jibda jseħħ mit-Tnej ...…
 
Steve Azar is a singer and songwriter that marries country, rock, and blues influences to create “Delta-Soul.” Inspired by the state of Mississippi, Steve wrote many successful tracks that topped the country charts including “Waitin’ On Joe,” “I Don’t Have to Be Me,” and “Sunshine.” After many ups and downs in the beginning of his career, Steve ...…
 
Did you know that dementia is predicted to become Australias leading cause of death in the next few years? Whilst there is currently no cure, a nutritional expert for older people believes you can actually cheat dementia by eating better food for the brain. - Kont taf li d-dimenzja hija mbassra li tkun il-kawża ewlenija tal-imwiet fl-Awstralja ...…
 
Al Ferox, also named Alessandro F., is an italian musician and producer, founder of the labels Dancefloor Killers, Kobayashi and Scream.He ran away from Italy to France at the age of 17, all that kept him going was his love for music.He got his first inspiration from his brothers vast record collection from 70’s listening bands as Black Sabbath ...…
 
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Horribly Off-Topic
 
Steve didn’t start remembering things until about 1987, Chris discovers that he’s an American medium, and Bill Skarsgård tries to fill Tim Curry’s big shoes. Enjoy the show?Subscribe to Horribly Off-Topic in iTunes, Stitcher, Google, Overcast, or via RSS. Then, throw a buck or three into our tip jar. Show Notes Worse Places to Be Than an Enya A ...…
 
Let f be nonconstant meromorphic. We want to show that [M(X): C(f)] is bounded by deg D, the divisor of poles of f.We do so by contradiction. If [M(X): C(f)] is at least k then we will get a lower bound for dim L(mD) for D sufficiently large in terms of k and m. Compare that with the upper bound 1 + deg(D) m to get contradiction,Take g_i linear ...…
 
Let f_0, …, f_n be a basis of L(D). Let phi: X to P^n be induced by f_i. Thus for p in X, if g is a meromorphic function st ord_p g = min ord_p f_i then phi(p) = [f_0/g(p), …, f_n/g(p)]. Identify P^n with P(L(D)*) by indetifying [0,…,1,…] with f_i*. Then phi(p) corresponds to the linear functional (sum f_i/g (p) f_i^*). Its kernel is the codime ...…
 
Let F be the largest divisor that occurs in every divisor of |D|, I.e. The fixed part of |D|, then D-F is base point free and L(D) = L(D-F).Since D-F leq D, we have one inclusion.If g is in L(D) then div g + D is in |D| so is equal to F + D' for some nonnegative D'. Thus div(g) + (D-F) is nonnegative…
 
Write D= P - N, nonnegative with disjoint support. We prove by induction on deg P.When deg P = 0, then as P is nonnegative I.e. All coefficient are nonnegative, P= 0. Then L(P) = L(0) is the the space of constant functions so must be of dim 1 ( because if div(f) geq 0 then all doff nonnegative but deg div f = 0, so all coefff is 0 and so f has ...…
 
Let f be a meromorphic function such that div(f) + D has no finite term. Then div(f) + D = deg D . infty If h is in L(D) then div(h) + D is geq 0 so div h - div f is geq- deg D. infty, thus h/f is a polynomial of deg at most deg D.Conversely if h= gf for g a polynomial of deg at most deg D then div(gf) + D = div(g) + div(f) + D geq div(g) + deg ...…
 
Suppose X is a compact Riemann surface.To each E in |D| (I.e, non negative, linearly equivalent to D), associate f such that E - D= div (f). Then f is unique up to nonzero scalar since if E - D = div(g) then div(f/g)= 0 so f/g has no poles or zeroes on C. Thus it is holomorphic on X and X is compact so it must be constant. But it has no zeroes ...…
 
Every projective line F= ax + by + cz = 0 is nonsingular (partials are a,b,c) and isomorphic to P^1 via projection to [y, z] if a is not 0.Every conic F= 0'correspond to symmetric matrix A. F is nonsingular iff A is invertible. This is because if V= (x,y,z) then the vector of partials of F at V is 2AV. Over C, every invertible symmetric matrix ...…
 
Suppose deg F = d. Let G = 0 be a hyperplane. Change coordinate to assume G= x and [0:0:1] is not in X. Then div(G) = divisor of zeroes of x/y so it's degree is just the size of fiber over 0 of x/y. Let h:X to Riemann sphere be the holomorphic map associated to x/y. Then deg(div (G)) is deg h, so it suffices to count size of fiber of h.Another ...…
 
Note: Divisors only need discrete support. If X is compact then support is finite so can define degree.If f:X to C is meromorphic then f is holomorphic as a map to Riemann Sphere so fibers over every point have same size (counting multiplicities), in particular over 0 and infinity. But these just correspond to number of zeroes and poles of f co ...…
 
Let X be the Zero of f(z,w) and p a node. Then the quadratic terms of the Taylor series expansion of f at p factors into distinct linear factors which lift to f= gh. Around p, the zeroes of X looks like zeroes X_g union with X_h. Delete p from all three and glue them together. The result is a Riemann surface (if f is irreducible) since at least ...…
 
Let X be zeroes of a f(z,w). Then p is a node of X if it is a singular point (I.e. Grad f vanish at p) but hessian f is not singular at p. In other words, the Taylor expansion of f at p has no constant term or linear term, and it's quadratic term factors into distinct homogeneous linear factors l_1, l_2. Around p, zeroes of f looks like union o ...…
 
Must then be isom to Riemann spheref gives a holomorphic map from X to the Riemann sphere. By open mapping theorem, image is open. As f is continuous, image is closed, so f is surjective.Counting fiber over infinity, we see that degree of f is 1 so f is injective.Bijective holomorphic maps are biholomorphic.…
 
If f is meromorphic on Riemann surface X then it can be viewed as a holomorphic function F to Riemann sphere. If p is not a pole then mult_p F = ord_p (f-f(p))If p is a pole then mulp_p F = - ord_p(f)
 
Ramification points of F are zeros of h' (F in coordinate), which is holomorphic, so must be discrete.F is holomorphic so must be an open map. If y is a branch point, I.e. Image of a ramification pt x then take a nghood U of x not containing any other ramification pt. then F(U) is a nghood of y not containing any other branch pt…
 
Let M be the Torus R^2/Z^2Recall the differential forms on the Torus pullback to differential forms on R^2 Thất are invariant under translation by lattice elements. Let a and b be the forms on M corresponding to dx, dy, resp. Then they are closed form since pi*(da) = d(pi*a) = d(d ) = 0 and pi* is an isomorphism. We show a wedge b is a basis of ...…
 
A differential form on R^2 is invariant under translation by a by its pullback under left translation by a is itself. Note that pullback of any w under F is w_F(F_*....), I.e. F^*w_q(X_i) = w_{Fq}(F_*X_i)Suppose w is pi^* t for some for some form t on Torus. Then as pi . l_a = pi for all a in the lattice, by functoriality of pullback we havel_a ...…
 
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Who the F is Kory Slater?
 
The Lord of the Rings, Game of Thrones style! An anchor baby. This show has turned into the most awesome Elder Scrolls game ever. iTunes Google Play Stitcher
 
Lebesgue: If f is a bounded function on a bounded set A in Rn then it is Riemann integrable iff its extension is continuous almost everywhere. In particular if f:U to R is continuous with compact support then it is Riemann integrable.A domain of integration is a bounded subset of Rn whose boundary has measure 0. If A is such a domain then every ...…
 
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What We Talkin Podcast & Convos With Drizz
 
What We Talking' Podcast Talkin On Subjects About What The F*** Is Cracking Da2Day With Different Guests.
 
Leaders is celebrating its tenth anniversary in 2017. In July, we threw a little party at the Getty Images Gallery in central London. We brought drinks, an ice sculpture, a magician, a caricaturist, some cupcakes and a microphone. We used the microphone to record a series of backstage interviews for this podcast.Casting an eye back at the miles ...…
 
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Who the F is Kory Slater?
 
Little Finger, "WTF?!" Dothraki Screamers!!!
 
Alright friends, in lieu of the 100+ multiple temps here in Portland, Father Lloyd and the Mr Burn decide to record the show in the comfort of the AC at Tanker Bar, featuring Ross Vegas and Fucking Gary. We don't need to say anything else but... We'll see you LIVE for not only Summer Slam, but also the 2nd ever live TankOver Portland Summer Sla ...…
 
A diffeomorphism F: (N, w_N) to (M, w_M) between oriented manifolds is called orientation preserving if the pullback of w_M is equivalent to w_N. If f: U to V is a diffeomorphism of open subsets of Rn with resp coords x_i and y_j then the standard orientation form for U and V are dx = dx1 ...dx_n and dy= dy_1... dy_n, resp. But we have the pull ...…
 
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Gifted Punksters
 
Kevin and Pat try to figure out what the f*** is "art?"
 
On a connected Manifold M, there is a bike tien between orientations and equivalence classes of smooth nowhere vanishing n forms on M. Where [X1, ..., Xn] is associated to w such that w(X1,...,Xn) is everywhere positive. (w and w' are equivalent if w = f w' for a positive function f).Explanation:- the space of n-covectors is of dim 1, so at eac ...…
 
Let m and v be two orientation on M. We need to show that either m= v or m= - v. Let f:M to {1, -1} be f(p)= 1 if m = v at p, and -1 if m= -v at p. Then as M is connected, to show Thay f is constant, it suffices to show that it is locally Constant.By continuity of m, v, they have continuous representative frames X_i, Y_j on some connected nghoo ...…
 
E.g. If f:R to R and g:R to R agree on an open set U, then so do their derivatives.An operator on a vector space is an endomorphism. An operator D on differential forms of M is local if whenever w1= w2 on U then Dw1 = Dw2 on U. E.g. Integration is not a local operator on smooth functions on [a,b].Antiderivation and derivation on diff forms are ...…
 
h: R to S1 is given by t maps to (cos t, sin t) Pullbacks of differential k-forms on S1 to R under h are periodic forms of period 2 pi.Suppose we have proven for k=0. For k = 1, notice that 1 forms on R are spanned (over 0-forms) by dt and 1 forms on S1 are spanned over 0-forms by w= -y dx + x dy. The pullback of f is pullback of f times pullba ...…
 
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Who the F is Kory Slater?
 
San Diego Comic Con trailer reviews of Thor: Ragnarock, Justice League, IT, and Ready Player One. Football is coming back, baby! Ohio State, Cleveland Browns, and Fantasy hopes for the 2017-2018 season. iTunes Google Play Stitcher
 
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Who the F is Kory Slater?
 
Jon Snow and Dani! Jon Snow and Tyrion! Lady Olenna Tyrell, LIKE A GOD DAMN BOSS!!!
 
In Episode 14, Tom chats with Union City, NJ up and comers, The Lo-Fis! They're fresh off a sold out show opening for Wolf Alice at Rough Trade NYC, where they shredded and witnessed some interesting celebrity gossip FIRST HAND. TUNE IN TO HEAR THIS JUICY INFO PLUS SONGS FROM THEIR BRAND NEW SINGLE, "TRIPPED ON A CURB!" Oh and of course they ma ...…
 
This week we go over the multitude of trailers released for SDCC. We have super secret leaks about Infinity War (Spoiler warning up) and an interview with F is For Family Co Creator and Simpsons writer Micheal Price. Personally I believe Phillip has killed.
 
Today, I’m thrilled to get to interview my favorite artist, Carrie Fell on Extraordinary Women Radio! I love, love, love her and and her work! You’ll love her great wisdom that she shares on engaging your creativity, on following your dreams, on stepping into your cowgirl courage! We talk about the importance of getting into the flow in our lif ...…
 
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Who the F is Kory Slater?
 
Ewwwwwww, Jorah. That's GROSS! I go off on the last 10 minutes of the episode for about 20 minutes, Strap your chairs in, it's a good ole' fashioned Kory Slater Bitch Fest.
 
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Crossover University
 
This week we go over the multitude of trailers released for SDCC. We have super secret leaks about Infinity War (Spoiler warning up) and an interview with F is For Family Co Creator and Simpsons writer Micheal Price. Personally I believe Phillip has killed.
 
This week Best Darn Diddly welcomes a very special guest to discuss the classic episode "Homer the Heretic". Simpsons writer Michael Price joins MrMostDaysOff & the WizKid to promote season 2 of his new show "F is for Family" which is available May 30th on Netflix. Michael talks about working with Bill Burr, Justin Long, and Sam Rockwell and he ...…
 
In general we cannot pushforward vector field X under F if F is not a diffeomorphism since:- the pushforward of all tangent vectors Xp might not cover whole codomain- F(p) might be equal to F(q) but the pushforward of X_F(p) could be different from Thất of X_F(q)However, if F is a Lie group homomorphism and X is a left-invariant vector field, t ...…
 
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