Best fis podcasts we could find (Updated December 2017)
Related podcasts: Kory Comedy Featured FM Silverscreen Ski Slipgate9 Edict Edictzero Slater Zero Shows Series Drama Fun Media Movies Tv Film Audio Fiction  
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show episodes
 
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Edict Zero - FIS
Rare
 
Edict Zero - FIS is a science fiction audio drama series produced by Slipgate Nine Entertainment. It is a cross of futuristic sci-fi, law enforcement procedural, crime, suspense/mystery, and dark fantasy.
 
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F is for Film
Weekly
 
As informative as half- assery permits, our three heroes Beanie, Dre, and Trent delve into all things film and TV related.
 
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Edict Zero – FIS
Rare
 
Home of the Science Fiction Audio Drama series
 
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F is for Friends
Daily+
 
Just friends being friendly.
 
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Who the F is Kory Slater?
Monthly+
 
Detailing the process of starting a comedy career in Los Angeles.
 
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C'Mon Son! The Podcast.
Weekly
 
C'Mon Son! The Podcast is hip-hop hall-of-fame inductee and Yo! MTV Raps legend Ed Lover's take on pop culture. Raw, rugged and unfiltered, this podcast gives listeners a break from "the expected," and will leave them wondering (while laughing hysterically), "what the f*** is wrong with Ed Lover?"
 
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HEAD TYROLIA (en) Bode Miller Special
 
HEAD TYROLIA Podcast Special – Bode Miller
 
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Elite Force Podcast
Monthly+
 
This Podcast Hosted By William" Walkie" Walker and Ashley Richardson as they brings you the News That is Going on in the World of Science Fiction. EFP is also Known for its Theme shows called EFP Presents. Past theme shows have covered Sci-Fis’ past and present in Tv,Movies,Video Games and Music. You Can Find The Elite Force Podcast at www.eliteforcepodcast.com
 
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M-F
Monthly+
 
M-F is a weekly daily podcast hosted by Sean and Amy. Link in bio.
 
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F's it all about ?
Rare
 
F's it all about ?What the F is it all about though? ...Conor & Dan take you through some of the common themes that millennials struggle to ascertain some meaning and satisfaction from in their everyday lives. Each episode is poised around one of these themes.
 
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CMD-F
Monthly
 
CMD-F is a podcast that aims to find and elevate stories that showcase exceptional people, places and things in Iowa City and beyond. Hosted by Alex Rose.
 
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What We Talkin Podcast & Convos With Drizz
 
Whats Going On People Listen Each Week As I Post Sit down Interviews With Artist And DJs In The Music Scene Of Manchester Plus Episodes Of The 'What We Talking' Podcast Talkin On Subjects About What The F*** Is Cracking Da2Day With Different Guests.DrizzCurrently On Legacy 90.1 Saturday From 6PM
 
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show series
 
The 2nd “Wave” of LINE’s smart speakers, self-driving taxis in Yokohama, plus SIM cards and Hue lights and drones working overtime! (Oh, my). And the wait is over: WiMAX! (And Pocket Wi-Fis, too!) All this & more on this week’s #ZettaiGeekDayo! As always, if you have any comments, questions or topics you’d like me to cover, please tweet them at ...…
 
*Wrestle Talk Family here is what we have in store on this week's show (Episode #172) *High Spots Segment where this week we discuss: What the F*** is Rusev day, WWE Tribute to the troops, Naito vs Omega and much more! *Shoot and Shout Segment: Joe, Rene and our guest get 60sec to go off on anything that might be ticking them off at the moment! ...…
 
F is For Family - Leaving a Legacy by New Community Church
 
An hour of sketchbook jams care from Dunedin's resident synth savant ISO12. ISO12 (Jason Aldridge) has been melting minds for years, both solo and with acts like Murdabike, Laser Cooling, and supergroup the Futurians - whose new album is due early next year on Feeding Tube Records. This hectic set was recorded live from his homebase at Steep St ...…
 
Justice League has come and gone, but that didn't stop the boys from chiming in to say our piece. TIME STAMPS WATCHED 1:18 NEWS 32:55 TRAILERS 55:30 MAIN 1:13:17 SPOILERS 1:20:00 If you want to touch base with us, hit us up below. Indie popcorn network Gmail: FisForFilmpod@gmail.com Instagram: FisForFilm Facebook: Facebook.com/FisForFilmpod Twi ...…
 
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New Community Church
 
F is for Family - Conflict by New Community Church
 
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Angry Dad Podcast
 
F! These Pills F! This Headache F! People Who Can’t Keep A Job
 
F is for Family - Technology and Family by New Community Church
 
Welcome to the weekly roundup of Netflix News. Our hosts break down what’s happening on the platform each week, and make sure you’re in the know about all things NETFLIX. Here’s what coming out for the week of November 12 – November 18: November 13 Chasing Trane: The John Coltrane Documentary Scooby-Doo 2: Monsters Unleashed November 14 DeRay D ...…
 
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F is for Friends
 
Friends
 
A conversation with with Dexter Paine, the Chair of the Board of U.S. Ski and Snowboard (USSA). Dexter also serves as a vice president and council member of the International Ski Federation (FIS). For his day job, he is a Founding Partner and Chair at the private equity firm Paine Schwartz Partners, LLC which focuses on sustainable food chain i ...…
 
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F is for Friends
 
Road Rebs
 
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GameEnthus Podcast - video games and everything else
 
GameEnthus Podcast ep323: MetaRoidVania or VREnthus This week Frank(@PSVRFrank) from YouTube joins Tiny(@Tiny415), Mike(@AssaultSuit) and Aaron(@Ind1fference) talk about: PSVR, HTC Vive, Weeping Doll, The Rift Report, Taco Bell, Cookout, PS Move, CheapassGamer, Star Trek Discovery, 60 Minutes, Sin and Punishment, Rakuga Kids, Sonic, Boogie Man, ...…
 
The "Music Connection Magazine Podcast" hosts - Randy Thomas and Arnie Wohl are back at it again, as they are rejoined by Senior Editor of the Music Connection Magazine Mark Nardone, who recaps the viral effect of the Foo Fighters: Dave Grohl's Storytelling segment from episode one. Randy & Arnie are also joined in-studio by guest Eric Vasquez ...…
 
Steve Azar is a singer and songwriter that marries country, rock, and blues influences to create “Delta-Soul.” Inspired by the state of Mississippi, Steve wrote many successful tracks that topped the country charts including “Waitin’ On Joe,” “I Don’t Have to Be Me,” and “Sunshine.” After many ups and downs in the beginning of his career, Steve ...…
 
Al Ferox, also named Alessandro F., is an italian musician and producer, founder of the labels Dancefloor Killers, Kobayashi and Scream.He ran away from Italy to France at the age of 17, all that kept him going was his love for music.He got his first inspiration from his brothers vast record collection from 70’s listening bands as Black Sabbath ...…
 
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Horribly Off-Topic
 
Steve didn’t start remembering things until about 1987, Chris discovers that he’s an American medium, and Bill Skarsgård tries to fill Tim Curry’s big shoes. Enjoy the show?Subscribe to Horribly Off-Topic in iTunes, Stitcher, Google, Overcast, or via RSS. Then, throw a buck or three into our tip jar. Show Notes Worse Places to Be Than an Enya A ...…
 
Let f be nonconstant meromorphic. We want to show that [M(X): C(f)] is bounded by deg D, the divisor of poles of f.We do so by contradiction. If [M(X): C(f)] is at least k then we will get a lower bound for dim L(mD) for D sufficiently large in terms of k and m. Compare that with the upper bound 1 + deg(D) m to get contradiction,Take g_i linear ...…
 
Let f_0, …, f_n be a basis of L(D). Let phi: X to P^n be induced by f_i. Thus for p in X, if g is a meromorphic function st ord_p g = min ord_p f_i then phi(p) = [f_0/g(p), …, f_n/g(p)]. Identify P^n with P(L(D)*) by indetifying [0,…,1,…] with f_i*. Then phi(p) corresponds to the linear functional (sum f_i/g (p) f_i^*). Its kernel is the codime ...…
 
Let F be the largest divisor that occurs in every divisor of |D|, I.e. The fixed part of |D|, then D-F is base point free and L(D) = L(D-F).Since D-F leq D, we have one inclusion.If g is in L(D) then div g + D is in |D| so is equal to F + D' for some nonnegative D'. Thus div(g) + (D-F) is nonnegative…
 
Write D= P - N, nonnegative with disjoint support. We prove by induction on deg P.When deg P = 0, then as P is nonnegative I.e. All coefficient are nonnegative, P= 0. Then L(P) = L(0) is the the space of constant functions so must be of dim 1 ( because if div(f) geq 0 then all doff nonnegative but deg div f = 0, so all coefff is 0 and so f has ...…
 
Let f be a meromorphic function such that div(f) + D has no finite term. Then div(f) + D = deg D . infty If h is in L(D) then div(h) + D is geq 0 so div h - div f is geq- deg D. infty, thus h/f is a polynomial of deg at most deg D.Conversely if h= gf for g a polynomial of deg at most deg D then div(gf) + D = div(g) + div(f) + D geq div(g) + deg ...…
 
Suppose X is a compact Riemann surface.To each E in |D| (I.e, non negative, linearly equivalent to D), associate f such that E - D= div (f). Then f is unique up to nonzero scalar since if E - D = div(g) then div(f/g)= 0 so f/g has no poles or zeroes on C. Thus it is holomorphic on X and X is compact so it must be constant. But it has no zeroes ...…
 
Every projective line F= ax + by + cz = 0 is nonsingular (partials are a,b,c) and isomorphic to P^1 via projection to [y, z] if a is not 0.Every conic F= 0'correspond to symmetric matrix A. F is nonsingular iff A is invertible. This is because if V= (x,y,z) then the vector of partials of F at V is 2AV. Over C, every invertible symmetric matrix ...…
 
Suppose deg F = d. Let G = 0 be a hyperplane. Change coordinate to assume G= x and [0:0:1] is not in X. Then div(G) = divisor of zeroes of x/y so it's degree is just the size of fiber over 0 of x/y. Let h:X to Riemann sphere be the holomorphic map associated to x/y. Then deg(div (G)) is deg h, so it suffices to count size of fiber of h.Another ...…
 
Note: Divisors only need discrete support. If X is compact then support is finite so can define degree.If f:X to C is meromorphic then f is holomorphic as a map to Riemann Sphere so fibers over every point have same size (counting multiplicities), in particular over 0 and infinity. But these just correspond to number of zeroes and poles of f co ...…
 
Let X be the Zero of f(z,w) and p a node. Then the quadratic terms of the Taylor series expansion of f at p factors into distinct linear factors which lift to f= gh. Around p, the zeroes of X looks like zeroes X_g union with X_h. Delete p from all three and glue them together. The result is a Riemann surface (if f is irreducible) since at least ...…
 
Let X be zeroes of a f(z,w). Then p is a node of X if it is a singular point (I.e. Grad f vanish at p) but hessian f is not singular at p. In other words, the Taylor expansion of f at p has no constant term or linear term, and it's quadratic term factors into distinct homogeneous linear factors l_1, l_2. Around p, zeroes of f looks like union o ...…
 
Must then be isom to Riemann spheref gives a holomorphic map from X to the Riemann sphere. By open mapping theorem, image is open. As f is continuous, image is closed, so f is surjective.Counting fiber over infinity, we see that degree of f is 1 so f is injective.Bijective holomorphic maps are biholomorphic.…
 
If f is meromorphic on Riemann surface X then it can be viewed as a holomorphic function F to Riemann sphere. If p is not a pole then mult_p F = ord_p (f-f(p))If p is a pole then mulp_p F = - ord_p(f)
 
Ramification points of F are zeros of h' (F in coordinate), which is holomorphic, so must be discrete.F is holomorphic so must be an open map. If y is a branch point, I.e. Image of a ramification pt x then take a nghood U of x not containing any other ramification pt. then F(U) is a nghood of y not containing any other branch pt…
 
Let M be the Torus R^2/Z^2Recall the differential forms on the Torus pullback to differential forms on R^2 Thất are invariant under translation by lattice elements. Let a and b be the forms on M corresponding to dx, dy, resp. Then they are closed form since pi*(da) = d(pi*a) = d(d ) = 0 and pi* is an isomorphism. We show a wedge b is a basis of ...…
 
A differential form on R^2 is invariant under translation by a by its pullback under left translation by a is itself. Note that pullback of any w under F is w_F(F_*....), I.e. F^*w_q(X_i) = w_{Fq}(F_*X_i)Suppose w is pi^* t for some for some form t on Torus. Then as pi . l_a = pi for all a in the lattice, by functoriality of pullback we havel_a ...…
 
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Who the F is Kory Slater?
 
The Lord of the Rings, Game of Thrones style! An anchor baby. This show has turned into the most awesome Elder Scrolls game ever. iTunes Google Play Stitcher
 
Mark F. is a career salary man whose ventures into ecommerce platform Alibaba to sell via Amazon has netted him more than $160,000 in his first 3 months. When I heard his story, I reached out because I believe a lot of people could benefit from his experiences and not only did he share his point of view, he dropped the essential gems of this wh ...…
 
Lebesgue: If f is a bounded function on a bounded set A in Rn then it is Riemann integrable iff its extension is continuous almost everywhere. In particular if f:U to R is continuous with compact support then it is Riemann integrable.A domain of integration is a bounded subset of Rn whose boundary has measure 0. If A is such a domain then every ...…
 
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What We Talkin Podcast & Convos With Drizz
 
What We Talking' Podcast Talkin On Subjects About What The F*** Is Cracking Da2Day With Different Guests.
 
Leaders is celebrating its tenth anniversary in 2017. In July, we threw a little party at the Getty Images Gallery in central London. We brought drinks, an ice sculpture, a magician, a caricaturist, some cupcakes and a microphone. We used the microphone to record a series of backstage interviews for this podcast.Casting an eye back at the miles ...…
 
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Who the F is Kory Slater?
 
Little Finger, "WTF?!" Dothraki Screamers!!!
 
Alright friends, in lieu of the 100+ multiple temps here in Portland, Father Lloyd and the Mr Burn decide to record the show in the comfort of the AC at Tanker Bar, featuring Ross Vegas and Fucking Gary. We don't need to say anything else but... We'll see you LIVE for not only Summer Slam, but also the 2nd ever live TankOver Portland Summer Sla ...…
 
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