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For compact X, L(D) is finite dim

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When? This feed was archived on December 09, 2017 16:01 (7y ago). Last successful fetch was on October 29, 2017 08:04 (7y ago)

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Manage episode 185577023 series 1521141
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Write D= P - N, nonnegative with disjoint support. We prove by induction on deg P. When deg P = 0, then as P is nonnegative I.e. All coefficient are nonnegative, P= 0. Then L(P) = L(0) is the the space of constant functions so must be of dim 1 ( because if div(f) geq 0 then all doff nonnegative but deg div f = 0, so all coefff is 0 and so f has no poles or zeroes. Thus f is holomorphic on a compact Riemann surface so f must be constant). As L(D) is a subspace of L(P), we must have dim L(D) is leq 1 which is leq 1 + deg (P) Suppose we prove that dim L(D) leq 1 + deg P for deg P = k-1. Now suppose deg P = k. Apply induction hypothesis for D-q and P- q where D(q) is at least 1. Then remember that dim L(D) leq dim L(D-q) + 1
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172 episodes

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Archived series ("Inactive feed" status)

When? This feed was archived on December 09, 2017 16:01 (7y ago). Last successful fetch was on October 29, 2017 08:04 (7y ago)

Why? Inactive feed status. Our servers were unable to retrieve a valid podcast feed for a sustained period.

What now? You might be able to find a more up-to-date version using the search function. This series will no longer be checked for updates. If you believe this to be in error, please check if the publisher's feed link below is valid and contact support to request the feed be restored or if you have any other concerns about this.

Manage episode 185577023 series 1521141
Content provided by Random Stuffs. All podcast content including episodes, graphics, and podcast descriptions are uploaded and provided directly by Random Stuffs or their podcast platform partner. If you believe someone is using your copyrighted work without your permission, you can follow the process outlined here https://player.fm/legal.
Write D= P - N, nonnegative with disjoint support. We prove by induction on deg P. When deg P = 0, then as P is nonnegative I.e. All coefficient are nonnegative, P= 0. Then L(P) = L(0) is the the space of constant functions so must be of dim 1 ( because if div(f) geq 0 then all doff nonnegative but deg div f = 0, so all coefff is 0 and so f has no poles or zeroes. Thus f is holomorphic on a compact Riemann surface so f must be constant). As L(D) is a subspace of L(P), we must have dim L(D) is leq 1 which is leq 1 + deg (P) Suppose we prove that dim L(D) leq 1 + deg P for deg P = k-1. Now suppose deg P = k. Apply induction hypothesis for D-q and P- q where D(q) is at least 1. Then remember that dim L(D) leq dim L(D-q) + 1
  continue reading

172 episodes

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